# Area of Median Triangle I

The sides of the trinagle BDG equal 2/3 of the corresponding medians. Its area is clearly 2/6=1/3 area of ΔABC. Thus the area of the median triangle (the triangle composed of the medians of ΔABC) equals (1/3)(3/2)²=3/4 that of ΔABC.

The assertion is a particular case of a more general statement. There is also another simple way to obtain this result.

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny

64463872 |