# Dissection of Triangle into Rhombus

## by Hubert Shutrick

The applet below illustrates Problem 8 from the 2010 All-Russian Olympiad:

In an acute triangle ABC, the median AM is longer than side AB. Prove that you can cut the triangle into three parts out of which you can construct a rhombus.

### This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at https://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.

 What if applet does not run?

Let M be the midpoint of BC and Bm the midpoint AC. Assume that BM < AB. Then there is point N on AB such that MN = AB. Cut over NM and BmM and swivel the two pieces 180°, one around Bm, the other around M. N' and N'' are the corresponding images of N and M' is the image of M under the rotation around Bm.

The proof that the construction leads to a rhombus is rather straightforward: all four sides of the resulting quadrilateral N'N''MM' equal AB.

(There is another attempt at solving the problem.)