# A Circle With Two Centers

How Is It Possible?

What if applet does not run? |

At points B and C of an angle BAC erect perpendiculars and let them intersect in D. Since AB and AC are not parallel, the perpendiculars are not parallel either. Thus, unless AB and AC form a 0° or a 180° angle, point D is well defined.

Draw a circle circumscribing ΔBCD. Besides B, the circle intersects AB in another point, say, E. It intersects AC in F different from C. Now, since ∠DBE is right, DE is a diameter of the circle. The midpoint of DE is the center of the circle. A similar argument applies to DF. As a result, we arrive at the conclusion that the circle at hand has two centers. How come?

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Copyright © 1996-2017 Alexander Bogomolny

What if applet does not run? |

The problem is with the drawing. Since both angles ABD and ACD are right, they both subtend a diameter of the circle, which is AD. Thus in all cases the points E and F coincide with A. (The applet cheats by drawing BD and CD not quite perpendicular to AB and AC.)

### References

- V. M. Bradis et al,
*Lapses in Mathematical Reasoning*, Dover, 1999, pp. 137-138

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|Activities| |Contact| |Front page| |Contents| |Geometry| |Fallacies| |Store|

Copyright © 1996-2017 Alexander Bogomolny

62018708 |