The 80-80-20 Triangle Problem, A Derivative, Solution #7
ABC is an isosceles triangle with vertex angle
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Copyright © 1996-2018 Alexander Bogomolny
This solution has been reported in [Which Way Did the Bicycle Go?].
Add a couple of triangles ACU and AUV equal to ΔABC and mark point F on AV,
∠ACE = ∠ECU - ∠ACU = 90° - 80° = 10°,
∠AEC = 180° - 20° - 10° = 150°.
Reference
- J. Konhauser, D. Velleman, S. Wagon, Which Way Did the Bicycle Go?, MAA, 1996, #15
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Copyright © 1996-2018 Alexander Bogomolny
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