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`(mu_(0)I)/(4r)``(mu_(0)I^(2))/(4r)``(mu_(0)I)/(4r^(2))`None of these

Answer :

ASolution :

According to Biot savart Law, the magnetic induction at a point to a current carrying elemnet i `delta` l is given by <br> `deltaB=(mu_(0))/(4pi)(ideltalxxr)/(r^(3))or B=(mu_(0))/(4pi)(ideltalsintheta)/(r^(2))` <br> Directed normal to plane containing `deltal` and <br> r theta being angle between `delta`l and r <br> r `theta` being angle between `delta` l and r <br> Magnetic field due to linear portions of wire <br> If we consider anuy element of lenth `deltal` of either linear portion ab or de, the angle between `delta` l and r is 0 or `pi` therefore. <br> `sintheta=0` <br> Hence, magnetic induction due to both linear portins of wire is <br> `(mu_(0))/(4pi)(ideltalsintheta)/(r)=0` <br> Field due to semi circular are <br> Now angle between a current element `delta` l of semi circular arc and the radius vector of the elment to point c is `pi//2` <br> Therefoe the magnitude of magnetic induction B at O due to this element is <br> `deltaB=(mu_(0))/(4pi)(ideltalsinpi//2)/(r^(2))=(mu_(0)ideltal)/(4pir^(2))` <br> Hence magnetic indution due to whole semi circular loop is `B=Sigma(mu_(0))/(4pi)(ideltal)/(r^(2))=(mu_(0))/(4pir^(2))=(mu_(0))/(4pi)(i)/(i^(2))Sigmadeltai=(mu_(0)i)/(4piR^(2))(pir)=(mu_(0)i)/(4r)` **Magnetic Force**

**FLEMING'S LEFT HAND RULE**

**Right Hand Rule**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PARALLEL/ANTIPARALLEL)**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PERPENDICULAR)**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE AT SOME ANGLE THAN 0, 90 AND 180**

**Magnetic Force On A Current Carrying Conductor**

**Magnetic Dipole Moment**

**Magnetic Dipole Moment In 3d**

**Magnetic Dipole In Uniform Magnetic Field**