Jumping Isn't Everything
Is it possible to move the counters from the left half of the board to the right? The only allowed move is to jump over an adjacent (vertically, horizontally, or diagonally) counter. (The jumped over counters are not removed.)
The applet above helps you experiment with the problem. Click on the counter you wish to move and then click on the empty space where you want to place the counter.
The task is impossible for an N×(N + 1) board with N odd as becomes clear from the following diagram
The counters originally located on the black spots will always stay on the black spots. The problem is there are six of them on the left and only three on the right.
Observe that removing up front one or two counters on the left still would not allow one to move the remaining ones to the right.
What happens when N is even? The task is still impossible, but for a slightly different reason. Introduce a system of coordinates
But clearly the number of, say, black spots in the left part of the board is different from their number on the right.
- M. Gardner, The Colossal Book of Short Puzzles and Problems, W. W. Norton, 2006, #10.12
- Pigeonhole Principle and Extensions
- Twenty five boys and twenty five girls
- Pigeonhole in Chess Training
- Married Couples at a Party
- Zeros and Nines
- Teams In a Tournament
- Divisibility of a Repunit
- Pigeonhole in Clubs