# Concurrent and Parallel Lines in Parallelogram

### What Might This Be About?

25 May 2014, Created with GeoGebra

### Problem

Through point $F$ on the diagonal $AC$ of parallelogram $ABCD$ draw to lines $EH$ and $GI$ where $E\in BC,$ $I\in CD,$ $H\in AD,$ $G\in AB.$

Prove that $GH\parallel EI.$

### Solution

There is a good deal of similar triangles, e.g., $\Delta AHF\sim\Delta CEH,$ $\Delta AGF\sim\Delta CIF.$ From these we derive proportions:

$\displaystyle\frac{AH}{EC}=\frac{AF}{CF}=\frac{AG}{CI}.$

Now, since also $\angle BAD=\angle BCD,$ $\Delta AGH\sim\Delta CIE,$ implying that one is obtained from the other with a homothety centered at $F$ and the coefficient $\displaystyle -\frac{AF}{CF}.$ This insures that $GH$ and $EI$ are indeed parallel.

### Acknowledgment

This problem has been posted by Dao Thanh Oai (Vietnam) at the CutTheKnotMath facebook page.

|Contact| |Front page| |Contents| |Geometry| |Store|

Copyright © 1996-2017 Alexander Bogomolny62069857 |