A Property of Isogonal Lines
What Might This Be About?
Problem
Given angle $BAC,$ line $AP,$ and its reflection in the bisector of $\angle BAC$, say $AP'.$ Let $P_b,$ $P_c$ be the projections of $P$ on the rays $AC$ and $AB,$ respectively.
Then $P_bP_c \perp AP'.$
Solution
The proof is simple.
Let $D$ be the intersection of $AP'$ and $P_bP_c.$ Then quadrilateral $AP_{b}PP_{c}$ is cyclic (and $AP$ is a diameter of its circumcircle.) Now, $\angle PP_{b}P_{c} = \angle PAP_{c}$ as two inscribed angles subtended by the same arc. It is also given that $\angle PAP_{c} = \angle DAP_{b},$ implying $\angle PP_{b}P_{c} = \angle DAP_{b}.$ The latter two angles have one pair of the sides perpendicular, therefore the same holds for the other pair of their sides.
Acknowledgment
References
- R. Honsberger, Episodes in Nineteenth and Twentieth Century Euclidean Geometry, MAA, 1995, p. 65
- R. A. Johnson, Advanced Euclidean Geometry (Modern Geometry), Dover, 1960, p. 156
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