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CTK Exchange
Olivier
guest
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Jul-01-09, 04:54 PM (EST) |
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"A mistake in Bear Cubs Problem?"
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Dear sir, As a former math researcher turned teacher, I enjoy your website tremendously. I may have misunderstood the statement, but I think there may be a mistake in the section Probability, Principle of Proportionality, Bear Cubs Problem. The problem: There are two bears, white and dark, one of which is known to be male. What is the probability that both are male? You state that the solution is 1/2 but I believe the solution is 1/3 (1/2 is the probability that both are male if, say, we know that the white one is male, but we have less information). Solution 1: Since they are distinguishable, the sample space consists of MM (for male/male), MF (for male/female), FM, and FF. If one of them is known to be male, then the sample space consists only of MM, MF, FF. Thus P(MM knowing at least one male) = 1/3. Solution 2: Let B be the event at least one male. Then P(B) = 3/4. Let A be the event both male, then P(A) = 1/4. Thus P(A knowing B) = P(A and B)/P(B) = P(A) / P(B) = 1/4 / 3/4 = 1/3. Solution 3: Using the Principle of Proportionality. Following your notation, we let A_1 = FF, A_2 = FM, A_3 = MF, and A_4 = MM. Then P(B knowing A_1) = 0 and P(B knowing A_4) = 1. But, contrary to what you write, P(B knowing A_2) = P(B knowing A_3) = 1 also. Thus, the sums of these probability is 3, so by the Principle of Proportionality, P(A_1 knowing B) = 0, P(A_2 knowing B) = P(A_3 knowing B) = P(A_3 knowing B) = 1/3. Best regards, Olivier
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alexb
Charter Member
2397 posts |
Jul-01-09, 06:59 PM (EST) |
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2. "RE: A mistake in Bear Cubs Problem?"
In response to message #0
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First, thank you for the kind words. But let's work out out differences. Looks very much like there is a mistake, indeed. Let's see what I had in mind when writing that page. I'll relate to your third solution. The question is whether P(B | A_2) = P(B | A_3) = 1 or P(B | A_2) = P(B | A_3) = 1/2. The difference, I believe, may be attributed to a bad wording of the definition of event B. You define "Let B be the event at least one male". I used in one place "Now assume I told you that one of the bears is male", "Assume it is known that one of the bears is male" in another, and "Event B is the acknowledgement that one of the bears is male" in the third. (The last two on the Proportionality Principle page.) I shall certainly have to have to work this out. However, let's consider several possibilities that might define event B.
- I've been watching the bear enclosure in the local zoo and saw a bear emerge from a cave that happened to be male. In this case, I believe, you would agree that if B is the awareness of the presence of a male bear, then P(B | A_2) = P(B | A_3) = 1/2.
- Assume it was not me who watched the bears but a small girl visiting the zoo. I overheard her exclaim, "Look mum a male bear." I believe that assuming the girl was correct, we still have P(B | A_2) = P(B | A_3) = 1/2.
- Now, as it happened, it was my wife and daughter who went to the zoo, while I stayed home to work on the site. When they returned from the zoo my daughter excitedly informed me of having seen a bear, "Daddy there was a male bear in the zoo." I believe that even in this case P(B | A_2) = P(B | A_3) = 1/2.
So, as I remember, in my mind, being told that there is a male bear played an essential role in defining the meaning of event B. It endowed event B with less certainty than emplied by your "Let B be the event at least one male". Does this make sense?
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