CTK Exchange
CTK Wiki Math
Front Page
Movie shortcuts
Personal info
Awards
Terms of use
Privacy Policy

Interactive Activities

Cut The Knot!
MSET99 Talk
Games & Puzzles
Arithmetic/Algebra
Geometry
Probability
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
My Logo
Math Poll
Other Math sit's
Guest book
News sit's

Recommend this site

Manifesto: what CTK is about Search CTK Buying a book is a commitment to learning Table of content Products to download and subscription Things you can find on CTK Chronology of updates Email to Cut The Knot Recommend this page

CTK Exchange

Subject: "Union of components in Riemann sphere is closed"     Previous Topic | Next Topic
Printer-friendly copy     Email this topic to a friend    
Conferences The CTK Exchange College math Topic #708
Reading Topic #708
George
guest
Jan-29-09, 09:07 PM (EST)
 
"Union of components in Riemann sphere is closed"
 
   The following is an exercise from page 32 of the 1952 edition of the book Analytic Functions by Stanislaw Saks and Antoni Zygmund (it is freely available online at
matwbn.icm.edu.pl/kstresc.php?tom=28&wyd=10&jez=pl):

If E is the extended complex plane (with the topology induced by the chordal metric) and if P, Q are closed sets in E, then the union of those components of the set P which have points in common with Q is also a closed set.

Every closed set in the extended complex plane is compact and if a sequence of points in the union converges to a point x in P then, for each point in the sequence one can find a point in Q in the same component of P. Since Q is compact there exists a convergent subsequence which converges to a point y in the intersection of P and Q since both are closed. It'seems that y and x should be in the same component of P. Can this be proven? If so, how? If not: is there another proof for the above?

Thank you


  Alert | IP Printer-friendly page | Reply | Reply With Quote | Top
alexb
Charter Member
2331 posts
Jan-31-09, 10:06 AM (EST)
Click to EMail alexb Click to send private message to alexb Click to view user profileClick to add this user to your buddy list  
1. "RE: Union of components in Riemann sphere is closed"
In response to message #0
 
   The union R = P∩Q is a closed set. Would it help if we assumed Q to be connected? Then the union S of all components of P with points common with Q is a connected set. Is S a component of R?


  Alert | IP Printer-friendly page | Reply | Reply With Quote | Top
George
guest
Jan-31-09, 11:45 AM (EST)
 
2. "RE: Union of components in Riemann sphere is closed"
In response to message #1
 
   I think I have found a proof:

If {x_n} is a sequence in the union of the components which converges to some point x, then x is in P since P is closed. For each n choose a point y_n in Q which lies in the same component as x_n. Since Q is compact there is a subsequence {y_n_i} which converges to some point y in the intersection of P and Q. Suppose x and y lie in different components of P, then there exists a number c>0 such that every sequence of points joining the points a and b in the set P has a characteristic number greater than or equal to c (this is proven on page 30 of the book by Saks and Zygmund mentioned above: "By the characteristic number of a finite sequence a_1,a_2,...,a_n of points of the plane we shall mean the largest of the distances
d(a_k, a_(k+1)) between consecutive points of this sequence. If all points of a finite sequence a=a_1,a_2,...,a_n=b belong to a certain set A, we say that this sequence joins the points a and b in A") But one can derive a contradiction since a closed set in the plane is connected if and only if for every c>0 it is possible for every two points a and b of this set to be joined in it by a finite sequence of points with characteristic number < c (Cantor's condition) (page 25 of the book) and for each i, x_n_i and y_n_i lie in the same component so, for every c>0, a finite sequence of points in P with characteristic < c and joining x and y can be found


  Alert | IP Printer-friendly page | Reply | Reply With Quote | Top

Conferences | Forums | Topics | Previous Topic | Next Topic

You may be curious to have a look at the old CTK Exchange archive.
Please do not post there.

Copyright © 1996-2018 Alexander Bogomolny

Search:
Keywords:

Google
Web CTK