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Subject: "proving the Chinese remainder theorem for more than 2 eqns"     Previous Topic | Next Topic
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Otto Murphy
guest
Mar-17-10, 08:42 PM (EST)
 
"proving the Chinese remainder theorem for more than 2 eqns"
 
   The proof provided on this website only proves the Chinese remainder theorem for two simultaneous equations. How can this be used to prove the theorem for more than two equations? Is there some kind of inductive argument?


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  Subject     Author     Message Date     ID  
  RE: proving the CRT for more than 2 eqns alexbadmin Mar-17-10 1
  RE: proving the Chinese remainder theorem for more than 2 Otto Murphy Mar-18-10 2
     RE: proving the Chinese remainder theorem for more than 2 alexbadmin Mar-18-10 3
         RE: proving the Chinese remainder theorem for more than 2 Otto Murphy Mar-19-10 5
     RE: proving the Chinese remainder theorem for more than 2 Otto Murphy Mar-19-10 4
         RE: proving the Chinese remainder theorem for more than 2 alexbadmin Mar-21-10 6
             RE: proving the Chinese remainder theorem for more than 2 alexbadmin Mar-23-10 7

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alexbadmin
Charter Member
2489 posts
Mar-17-10, 09:00 PM (EST)
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1. "RE: proving the CRT for more than 2 eqns"
In response to message #0
 
   Yes, sure. Induction works pretty simple. I'll add a few lines tomorrow.


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Otto Murphy
guest
Mar-18-10, 09:53 PM (EST)
 
2. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #0
 
   How do you know that s = n_k 1 (mod gcd(lcm(m1, m2, ..., mk)), m_k 1)?


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alexbadmin
Charter Member
2489 posts
Mar-18-10, 09:56 PM (EST)
Click to EMail alexb Click to send private message to alexb Click to view user profileClick to add this user to your buddy list  
3. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #2
 
   Did I write that? Or is it implicit'somewhere in what I wrote?


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Otto Murphy
guest
Mar-19-10, 11:08 PM (EST)
 
5. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #3
 
   P.S. the pluses are not appearing in the posts.


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Otto Murphy
guest
Mar-19-10, 11:08 PM (EST)
 
4. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #2
 
   Don't you have to show that:

s = n_k+1 (mod gcd(lcm(m1, m2, ..., mk), m_k+1))

is true before you can find n:

n = s (mod lcm(m_1, m_2, ..., m_k))
n = n_k+1 (mod m_k+1)

I can't figure out how to prove that the first eqn. is true.


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alexbadmin
Charter Member
2489 posts
Mar-21-10, 11:20 PM (EST)
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6. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #4
 
   Oh, must be senility. Many thanks.

I'll fill in tomorrow.


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alexbadmin
Charter Member
2489 posts
Mar-23-10, 11:55 AM (EST)
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7. "RE: proving the Chinese remainder theorem for more than 2"
In response to message #6
 
   Sorry for being tardy. I have expanded the proof, although there is one detail that needs further attention. I would like to make a reference but could not find one. So there is a need for a page on the properties of the gcd, lcm and congruencies. Lately, I've been into something else and this I have to finish first. I'll post here when everything is done.


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