|
|
|
|
|
|
|
|
CTK Exchange
Greg
guest
|
Sep-21-09, 11:44 PM (EST) |
|
|
"Pascal's theorem, homogeneous coordinates"
| |
Hey Alex, Long time, no talk. I've been looking at this proof https://www.cut-the-knot.org/pythagoras/Chasles/Pascal.shtml How do you justify being able to choose A,C,E as (1,0,0), (0,1,0), (0,0,1)? Greg |
|
|
Alert | IP |
Printer-friendly page |
Reply |
Reply With Quote | Top |
|
|
alexb
Charter Member
2439 posts |
Sep-21-09, 11:45 PM (EST) |
    |
1. "RE: Pascal's theorem, homogeneous coordinates"
In response to message #0
| |
It is possible to projectively map any three points to the vertices of an equilateral triangle so that their barycenter maps onto the center of the triangle. In the associated homogeneous coordinates the three points will have the coordinates (1,0,0), (0,1,0), (0,0,1).
|
|
|
Alert | IP |
Printer-friendly page |
Reply |
Reply With Quote | Top |
|
|
You may be curious to have a look at the old CTK Exchange archive.
Please do not post there.
![]()
Copyright © 1996-2018 Alexander Bogomolny
|
|
Printer-friendly copy
Email this topic to a friend