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Subject: "Monge's Theorem via Desargues"     Previous Topic | Next Topic
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Don Johnson
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Apr-19-09, 02:41 PM (EST)
 
"Monge's Theorem via Desargues"
 
   Off of the cut the knot website( https://www.cut-the-knot.org/Curriculum/Geometry/MongeDesargues.shtml ) it'shows how to prove Monge's Thoerem via Desargues, but it doesn't tell why A1B1||A2B2||A3B3. Can somebody please explain to me why those lines are parallel.


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alexb
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2361 posts
Apr-19-09, 03:12 PM (EST)
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1. "RE: Monge's Theorem via Desargues"
In response to message #0
 
   It's the third time in a couple of weeks that I am asked this question. I'd be grateful if you go around and discuss this problem with your classmates.

Make this drawing:

Pick point X and produce from it three rays Xa, Xo, Xb. On Xo choose points O1 and O2, on Xa points A1 and A2, and on Xb points B1 and B2. Points O are entirely arbtrary, but make an effort to choose points A and B so that O1A1||O2A2 and O1B1||O2B2. You will then see that A1B1||A2B2. Try to think why is this so. (Hint: it has to do with similarity of triangles and the fact that in similar triangles side lengths are in a proportion.)


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Don Johnson
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Apr-20-09, 07:05 PM (EST)
 
2. "RE: Monge's Theorem via Desargues"
In response to message #1
 
   Thanks for the help. Sorry that you had to do this problem 3 times in a couple of weeks. If I found it on the forums I wouldn't have asked.


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