|
|
|
|
|
|
|
|
CTK Exchange
alexb
Charter Member
2478 posts |
Mar-08-10, 00:21 AM (EST) |
    |
1. "RE: Clarification on proof #82 of pythagorean theorem please"
In response to message #0
| |
>I understand that based on the similarity between Triangle
>ABC and DBE that the AA similarity dictates that
>x/(a-x)=b/c, but i do not understand how in the next step,
>x=ab/(b+c). i have tried all the similarity equations but i
>cannot find a way to find that value of x. Thank you in
>advance. This is plain algebra. x / (a - x) = b / c xc = (a - x)b xc = ab - xb xb + xc = ab x(a + b) = bc x = bc / (a + b) |
|
|
Alert | IP |
Printer-friendly page |
Reply |
Reply With Quote | Top |
|
|
You may be curious to have a look at the old CTK Exchange archive.
Please do not post there.
![]()
Copyright © 1996-2018 Alexander Bogomolny
|
|
Printer-friendly copy
Email this topic to a friend