# Grandfather's Bill

This is a problem from the 1947 Stanford Competitive Examination []:

Among grandfather's papers a bill was found

72 turkeys $_67.9_

The first and the last digits of the number that obviously represented the total price of those fowls are replaced here by underscores, for they have faded and are now illegible.

What are the two faded digits and what was the price of one turkey?

### Reference

- G. Polya, J. Kilpatrick,
*The Stanford Mathematics Problem Book*, Dover, 2009 - G. Polya,
*Patterns of Plausible Inference*, Ishi Press (July 13, 2009)

|Contact| |Front page| |Contents| |Arithmetic|

Copyright © 1996-2018 Alexander Bogomolny

Among grandfather's papers a bill was found

72 turkeys $_67.9_

The first and the last digits of the number that obviously represented the total price of those fowls are replaced here by underscores, for they have faded and are now illegible.

What are the two faded digits and what was the price of one turkey?

### Solution

The key to the solution is the the criteria of the divisibility by 9 and by 8, for, after all,

A number is divisible by 8 iff and only if the number formed by its three,one,two,three,eight last digits is divisible by 8. From grandfather's bill, we have a three-digit number 79x, where x is the unknown last digit. However,

What is remains is to find the first digit. Divisibility by 9 comes to rescue. A number is divisible by 9 iff the sum of its digits,the sum of its digits,the sum of odd digits,the last digit is divisible by 9. Let the unknown first digit be y. Then the sum

y + 6 + 7 + 9 + 2 = y + 24

must be divisible by 9, meaning that y + 6,y + 3,y + 6,y + 9 must be divisible by 9. From hereThe price of the single turkey was $367.92 / 72 = $5.11.

|Contact| |Front page| |Contents| |Arithmetic|

Copyright © 1996-2018 Alexander Bogomolny

64266547 |