# Three Similar Polygons

The following problem and its generalization have been discussed elsewhere:

Suppose A, B, C are arbitrary points on a straight line and X is a point not on the line. Construct similar and similarly oriented triangles ABX and BCY. If triangle XYZ is similar to triangles ABX and BCY but with a different orientation then Z is always collinear with A, B, and C!

The applet below presents an additional twist. Consider similar polygons: ABX0X1...XN, BCY0Y1...YN, X0Y0Z0...ZN. The problem above implies that if one of the vertices Xi, i > 0, lies on the line X0Y0, then the vertex Zi lies on AB. Perhaps a little more surprising is the fact that if Xi lies on AB then Zi lies on X0Y0, whereas Xi and Yi are always on the same line: either both are on X0Y0 or both are on AB.

### This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at https://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.

 What if applet does not run?