Segment Trisection
What Is It About?
A Mathematical Droodle

14 October 2015, Created with GeoGebra

Segment Trisection

The applet suggests the following statement:

From a point T on the base AB of ΔABC draw lines parallel to the medians AM_a and BM_b. Let D and H be the points of intersection of those lines with AC and BC, respectively. Then the medians AM_a and BM_b trisect the segment DH.

14 October 2015, Created with GeoGebra

Proof

Let the notations be as in the diagram. In particular, G denotes the centroid of the triangle. This implies

(1)

GM_b = BM_b / 3.

Next note that similar triangles ABM_b and ATD are divided by the median AM_a into two pairs of similar triangles, from which with the help of (1)

(2)

DK = DT / 3.

Now, triangles DTH and DKE are also similar, so that (2) implies

(3)

DE = DH / 3.

Similarly, FH = DH/3. Therefore, DE = EF = FH.

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Segment TrisectionWhat Is It About? A Mathematical Droodle