# Counting Triangles and Segments in a Polygon

This is an extension of the problem of diagonal count in a convex polygon. Now, we have an N-gon, i.e. a polygon with N vertices and N sides and M additional points in its interior. Connect all the given points without intersection until no segments could be added. Count the number of added segments and the triangles formed along the way. What can you say about the two numbers?

What if applet does not run? |

(Points are connected by dragging the cursor from one to the other.)

|Activities| |Contact| |Front page| |Contents| |Geometry| |Store|

Copyright © 1996-2017 Alexander Bogomolny

The number of segments and triangles depends only on the numbers M and N.

Let, when no additional segments could be drawn, there be K triangles. Angles in K triangles sum up to 180°K. We may find the same quantity in a different way. Internal angles of the N-gon add up to

180°K = 180°(N - 2) + 360°M, or K = N - 2 + 2M. |

So that the number of triangles is always

K triangles have the total of 3K sides, of which N belong only to one triangle, while the rest belong to two triangles each. The latter are exactly the segments that have been added by construction and whose number we are looking for. It's therefore equals

(3K - N)/2 = (3N - 6 + 6M - N)/2 = N - 3 + 3M. |

|Activities| |Contact| |Front page| |Contents| |Geometry| |Store|

Copyright © 1996-2017 Alexander Bogomolny

61183766 |