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Newton's Theorem: What is it?
A Mathematical Droodle


This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


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Explanation

Copyright © 1996-2008 Alexander Bogomolny

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Newton's and Léon Anne's Theorems

The applet illustrates the following statement (Newton's theorem):

 

The center of the circle inscribed into a quadrilateral lies on the line joining the midpoints of the latter's diagonals.

The line is known as Newton's line. It exists for the quadrilaterals that are not parallelograms.

The statement is an immediate consequence of a theorem of Léon Anne:

Theorem (Pierre-Léon Anne, 1806-1850)

 

In any quadrilateral ABCD that is not a parallelogram, the locus of points O such that

Area(AOB) + Area(COD) = Area(BOC) + Area(AOD)

is Newton's line of the quadrilateral.

Proof of Newton's Theorem

For any quadrilateral ABCD circumscribed around a circle AB + CD = BC + AD. (This is because two tangents from a point to a circle are equal. To derive the identity, consider four pairs of tangents -- one at each vertex of the quadrilateral.) Multiply that identity by R/2, where R is the radius of the circle, to obtain Area(AOB) + Area(COD) = Area(BOC) + Area(AOD). By the theorem of Léon Anne, the proof is complete.

Proof 1 of the theorem of Léon Anne

[F. G.-M, p. 767]. Since E is the midpoint of the diagonal BD, the lengths of the perpendiculars from BD onto the line EF are equal. Therefore, say, triangles BOF and DOF have equal areas. Similarly, Area(AOF) = Area(COF). Further,

  Area(AOB) = Area(AFB) + Area(AOF) + Area(BOF) and
Area(DOC) = Area(DFC) - Area(COF) - Area(DOF).

Therefore

(1) Area(AOB) + Area(COD) = Area(AFB) + Area(CFD).

In the same manner,

  Area(AOD) = Area(AFD) + Area(DOF) - Area(AOF) and
Area(BOC) = Area(BFC) - Area(BOF) + Area(COF).

Wherefrom

(2) Area(AOD) + Area(BOC) = Area(AFD) + Area(CFB).

But we know that Area(AFB) = Area(AFD) and also Area(CFD) = Area(CFB), which, combined with (1) and (2), yields

(3) Area(AOD) + Area(BOC) = Area(AOB) + Area(COD).

Proof 2 of the theorem of Léon Anne

[Honsberger, p. 174-175]

Since a median bisects the area of a triangle, the midpoints of the diagonals of the quadrilateral lie one the locus in question. An observation due to Basil Rannie makes it clear that the locus is a straight line.

The area of a triangle with a fixed base and a moving apex is the linear function of the Cartesian coordinates of the latter. If the apex is shared by two triangles, their total area is still a linear function of its coordinates. But the level curves of a linear function are straight lines.

References

  1. F. G.-M., Exercices de Géométrie, Jacques Gabay, 1991
  2. R. Honsberger, More Mathematical Morsels, MAA, 1991

Copyright © 1996-2008 Alexander Bogomolny

28695577Page copy protected against web site content infringement by Copyscape


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