Angles in a Cube I
Let denote the vertices of a cube ABCD (for the bottom face) and A'B'C'D' (for the top face), with A' above A, etc. What is the angle AB'C?
| Buy this applet What if applet does not run? |
|Activities| |Contact| |Front page| |Contents| |Geometry| |Store|
Copyright © 1996-2015 Alexander BogomolnySolution
Add to the picture the side AC. As all three segments AB', B'C and AC are the diagonals of equal squares, they are equal and, thus, form an equalteral triangle, implying that angle AB'C is 60°.
| Buy this applet What if applet does not run? |
Related material
| |
|
| |
|
| |
|
| |
|
| |
|
| |
|
| |
|
| |
|Activities| |Contact| |Front page| |Contents| |Geometry| |Store|
Copyright © 1996-2015 Alexander Bogomolny| 49552117 |

