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Angles in a Cube I
Let denote the vertices of a cube ABCD (for the bottom face) and A'B'C'D' (for the top face), with A' above A, etc. What is the angle AB'C?
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Solution
Copyright © 1996-2010 Alexander Bogomolny
Solution
Add to the picture the side AC. As all three segments AB', B'C and AC are the diagonals of equal squares, they are equal and, thus, form an equalteral triangle, implying that angle AB'C is 60°.
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Copyright © 1996-2010 Alexander Bogomolny
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