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Pilar
guest
Mar-13-06, 02:32 PM (EST)
 
"Let's see"
 
   Hi,i have a silly "game" for you to play with.
Maybe it has appeared before, but it's fun anyway.
Here it goes:
x=1
x^2=1
x^2-1=0
(x+1)(x-1)=0
<(x+1)(x-1)>/(x-1)=0
x+1=0
1+1=0
2=0
Find the mistake!
Nice site, i love it.
See you


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marcus
guest
Mar-18-06, 07:51 AM (EST)
 
1. "RE: Let's see"
In response to message #0
 
   (x+1)(x-1)>/(x-1)=0 !!!

Dividing by zero is forbidden, otherwise you get any result you want.


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