Let ABCD be a plain convex quadrilateral. P, Q are points of AD and BC respectively such that

\frac{AP}{PD} = \frac{AB}{DC} = \frac{BQ}{QC}.

Show that the angles that are formed by the lines PQ with AB and CD are equal.

**Solution by Steve Dinh, a.k.a. Vo Duc Dien (dedicated to the lovely Quynh-Diep Katrina Ngo)**

From P draw a line || to DC and intercept AC at I. Link IQ. We have IQ || AB. We then have ∠QEC = ∠QPI and ∠QFB = ∠PQI.

To prove that the angles that are formed by the lines PQ with AB and CD are equal, we then need to prove ∠QPI = ∠PQI,

or IP = IQ.

From I draw a line parallel to AD and intercept DC at J. We have

or

We also have \frac{AB}{DC} = \frac{AP}{PD} = \frac{IP}{JC};

Therefore, IP = IQ.