Professor McWorter sent me a one page paper he came across while rummaging through some old stuff. The paper appeared in Eureka, Vol. 2, no. 8, October, 1976, p. 162. It's reproduced below as accurately as possible. Two footnotes are either Bankoff's or the journal editor's. The second one is especially noteworthy.
A DIRECT GEOMETRICAL PROOF OF MORLEY'S THEOREM
EUCLIDE PARACELSO BOMBASTO UMBIGIO, Guyazuela
MORLEY"S THEOREM. The intersections of the adjacent internal angle trisectors of a triangle are the vertices of an equilateral triangle.
Proof1. Extend BZ and CY to meet at P (see figure). On the segment PC, let PQ = PB, and let L be the projection of Z on BQ. Construct CD parallel to BQ and let M, N denote projections of Y, Q on CD.
But YM - ZL = QN; hence YC - ZB = QC. But YC - YQ = QC. Therefore YQ = ZB; and since PQ = PB, it follows that PZ = PY. Then, since X is the incenter of triangle BCP, PX bisects the angle BPC, and triangles XYP and PZX are congruent. So ZX = XY. Similarly, it can be shown that ZY = ZX = XY.