Morley's Miracle Bankoff's proof
This proof has appeared in Mathematics Magazine, 35 (1962) 223-224.
In the diagram,
| (1) |
sin( AQC) | = sin(p - (A+C)/3) |
| | = sin((p - B)/3) |
| | = sin((2p + B)/3) |
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Also
| (2) |
sin(3a) = 4sin(a)sin(p/3 + a)sin(p/3 - a)
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From the Sine Law,
AQ·sin((p - B)/3) = 2R·sin(B)·sin(C/3),
where R is the circumradius. Therefore, by (2)
AQ = 8R·sin(B/3)·sin(C/3)·sin((p + B)/3).
Similarly, AR = 8R·sin(C/3)·sin(B/3)·sin((p + C)/3). Therefore,
AR/AQ = sin((p + C)/3)/sin((p + B)/3).
But ARQ + AQR = p - A/3 = (p + B)/3 + (p + C)/3. From here,
ARQ = (p + C)/3 and AQR = (p + B)/3,
and similarly for triangles BPR and CPQ. It thus follows that the sum of angles around P, excluding QPR is 300o, or QPR = 60o. The other two angles are similarly shown to be 60o.

Morley's Miracle
- J.Conway's proof
- Newman's proof
- Bankoff's proof
- Another proof
- Nikos Dergiades' proof
- G. Zsolt Kiss' proof
- M. T. Naraniengar's proof
- Doodling and Miracles
- Morley's Pursuit of Incidence
- Lines, Circles and Beyond
- On Motivation and Understanding
- Bankoff's Conundrum
- Morley's Redux and More, Alain Connes' proof
- An Unexpected Variant

Copyright © 1996-2008 Alexander Bogomolny
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