# Round Carpets

In the diagram below, which areas are bigger - the yellow 'almonds' or the pink 'umbrellas'?

|Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander BogomolnyIn the diagram below, which areas are bigger - the yellow 'almonds' or the pink 'umbrellas'?

### Solution

We shall apply the Carpets Theorem

Assume shape U is split in two ways

U = S_{1} ∪ S_{2} = T_{1} ∪ T_{2},

such that Area(T_{1}) = Area(S_{2}). Then

Area(S_{1} ∩ T_{1}) = Area(S_{2} ∩ T_{2}).

Imagine the big circle U split in two ways as shown:

(I assume that, say, S_{1} is the union of two circles, and similarly T_{1}.)

Since the area of a circle of radius ρ equals πρ², Area(T_{1}) = Area(S_{1}) = ½Area(U). Therefore, also _{1}) = Area(S_{2})

Area(S_{1} ∩ T_{1}) = Area(S_{2} ∩ T_{2}),

which is to say that the yellow almonds have the same area as the pink umbrellas.

**Note**: In general, the Carpets Theorem just claims the obvious fact that if shifting (or placing) a piece of a carpet creates an overlap with another piece then the area of the floor uncovered (not covered) due to the shift (placement) equals the area of the overlap. The theorem applies because the areas of the four small circles add up to the area of the big one. So what they fail to cover needs to be equal to what they cover redundantly. (I thank John Golden for reminding me of this simple interpretation.)

### Carpets Theorem

- The Carpets Theorem
- Carpets in a Parallelogram
- Carpets in a Quadrilateral
- Carpets in a Quadrilateral II
- Square Root of 2 is Irrational
- Carpets Theorem With Parallelograms
- Two Rectangles in a Rectangle
- Bisection of Yin and Yang
- Carpets in Hexagon
- Round Carpets
- A Property of Semicircles
- Carpets in Triangle
- Carpets in Triangle, II
- Carpets in Right Triangle
- Piecewise Carpets in Parallelogram

|Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny65404918 |