A Neglected Pythagorean-Like FormulaA generalization of the Pythagorean Theorem has been published by Larry Hoehn (2000), whose article has been also included in C. Pritchard's collection.
In an isosceles triangle with sides c draw a cevian of length a and assume its foot divides the base into segments b and d. Then [Hoehn]
The statement is a clear generalization of the Pythagorean theorem. The latter is obtained when the selected cevian coincides with the axis of symmetry (altitude, median, angle bisector) of the triangle, i.e. the case where On the other hand, (1) can be derived by a double application of the Pythagorean theorem. Indeed, let the triangle be ABD, with the cevian BC. Draw the axis BE. From the right triangle ABE,
From the right triangle CBE,
Subtracting (3) from (2) we get
where (with FE = EC) AE + EC = AF = CD = d.
The proof reminds one of a proof of the law of cosines to which (1) appears to be related. Indeed, d = CD = AF = AC + 2·EC, so that (1) is the same as
which is Euclid II.12 for On the other hand, b = AC = DF = DC - 2·EC. Thus (1) is the same as
which is Euclid II.13 for This is a nice property: a single formula (1) covers both cases - for obtuse and acute angles - that Euclid treats separately. This is exactly a feature of the law of cosines, where the behavior of cosine absorbs the change of sign between (5) and (6). RemarkNathan Bowler observed that a simpler proof is obtained from the intersecting chords theorem applied in a circle with radius c centered at B. Extend BC in both directions to the intersection with the circle. Now you have two chords that meet at C: (c - a)·(c + a) = bd. Ricardo Sandoval adds to that that point C may lie outside segment AD in which case Power of a Point theorem leads to (a - c)·(a + c) = bd, or the same identity with one of b or d thought negative. References
Power of a Point wrt a Circle
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