Cut the knot: learn to enjoy mathematics
A math books store at a unique math study site. Learn to enjoy mathematics.
Google
Web CTK
Best sites for teachers
Sites for teachers
Sites for parents
Terms of use
Awards

Interactive Activities
CTK Exchange
CTK Insights - a blog

Games & Puzzles
What Is What
Arithmetic/Algebra
Geometry
Probability
Outline Mathematics
Make an Identity
Book Reviews
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
Visual Illusions
My Logo
Math Poll
Cut The Knot!
MSET99 Talk
Other Math sites
Front Page
Movie shortcuts
Personal info
Reciprocal links
Privacy Policy

Guest book
News sites

Recommend this site

Best sites for teachers
Sites for teachers
Sites for parents

Education & Parenting

Manifesto: what CTK is about Search CTK Buying a book is a commitment to learning Table of content Things you can find on CTK Chronology of updates Email to Cut The Knot Recommend this page

The Lepidoptera of the Quadrilateral

The Butterfly Theorem is one of the most popular and appealing in plane geometry. It has several variants and a few curious generalizations. Until very recently, all the known varieties of plane Butterflies were found in circles and their combinations. But no longer. A new variety that inhabits quadrilaterals has been just discovered. We can compare the typical species side by side:

 

The closest to the newly discovered is that described by Steve Conrad: Through a point I on a chord AC of a circle, two other chords EF and HG are drawn. If EG and HF intersect AC in M and N, respectively, then

  1/IM - 1/IA = 1/IN - 1/IC.

If we introduce a = IA, m = IM, c = IC, n = IN, then the above will appear as

(1) 1/m - 1/a = 1/n - 1/c.

The new variety has been described by S. Kung:

Theorem

Through the intersection I of the diagonals AC, BD of a convex quadrilateral ABCD, draw two lines EF and HG that meet the sides of ABCD in E, F, G, H. Let M and N be the intersections of EG and FH with AC. Then (1) holds.

The proof of the theorem is based on two simple lemmas.

Lemma 1

If K is the intersection of segments XY and UV, V distinct from K, then

  Area(UXY)/Area(VXY) = UK/VK.

 

This is true because the two triangles share a base. Their areas therefore are in the ratio of their altitudes. The latter, along with XY and UV, cut two similar right triangles, in which the ratio of the corresponding sides is UK/VK.

Lemma 2

Given triangles ABC and XYZ such that either ABC = XYZ or ABC + XYZ = 180o. Then

 
  Area(ABC)/Area(XYZ) = AB/XY·BC/YZ.

The proof is similar to that of Lemma 1.

Proof of Theorem

 

There are 12 pairs of triangles to which we may apply either Lemma 1 or Lemma 2. We get successively

 
AM/IM= Area(AEG)/Area(IEG)
IN/CN= Area(IHF)/Area(CHF)
IC/IA= Area(CBD)/Area(ABD)
IE/IF·IG/IH= Area(IEG)/Area(IHF)
CH/BC·CF/CD= Area(CHF)/Area(CBD)
AB/AE·AD/AG= Area(ABD)/Area(AEG)
IF/IE= Area(AFC)/Area(AEC)
IH/IG= Area(AHC)/Area(AGC)
CD/CF= Area(CAD)/Area(AFC)
BC/CH= Area(ABC)/Area(AHC)
AE/AB= Area(AEC)/Area(ABC)
AG/AD= Area(AGC)/Area(CAD)

Multiplying all twelve yields

  AM/IM·IN/CN·IC/IA = 1,

or

  (a - m)/m·n/(c - n)·c/a = 1.

Rewriting this once more we obtain

  (a - m)/(am) = (c - n)/(cn),

which is the same as (1).

We should note that the new variety of butterflies admits generalizations similar to their circular relatives. For example, based on the same consideration we can claim the existence of 2N-winged butterflies dwelling on (co-diagonal) rectangles.

References

  1. S. Kung, A Butterfly Theorem for Quadrilaterals, Math Magazine 78 (Oct. 2005), pp. 314-316

Butterfly Theorem and Variants

  1. Butterfly theorem
  2. 2N-Wing Butterfly Theorem
  3. Better Butterfly Theorem
  4. The Lepidoptera of the Circles
  5. The Lepidoptera of the Quadrilateral
  6. The Lepidoptera of the Quadrilateral II
  7. Butterflies in Quadrilaterals and Elsewhere
  8. Two Butterflies Theorem
  9. Two Butterflies Theorem II
  10. Two Butterflies Theorem III

Copyright © 1996-2008 Alexander Bogomolny

28737518Page copy protected against web site content infringement by Copyscape


Search:
Keywords:


Latest on CTK Exchange
Math
Posted by Laura
2 messages
06:56 AM, Apr-15-08

Divisibility rules - Jargon buste ...
Posted by Carolyn
2 messages
08:35 AM, Apr-04-08

drawing puzzle
Posted by martin gran
31 messages
06:53 PM, May-09-08

conway's game of life
Posted by frequency
0 messages
11:52 PM, May-12-08

Mistake on the page (an aside, Be ...
Posted by Max
4 messages
10:28 AM, Feb-28-08

Deriving functions based on diffe ...
Posted by ke_45
1 messages
12:47 PM, May-10-08

Josephus Flavius (correction)
Posted by David Turner
1 messages
09:42 AM, May-14-08