Infinitude of Primes
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| (1) | F0·F1·F2·...·Fn-1 = Fn - 2, n ≥ 1. |
Proof
The proof is by induction. Since F0 = 3 and F1 = 5, (1) is indeed true for k = 1. Assume it holds for
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Lemma 2
For n ≠ m, Fn and Fm are mutually prime.
Proof
Indeed, assume t divides both Fn and Fm,
Fn = F0·F1·...·Fm·...·Fn-1 - 2,
implying that t divides
F0·F1·...·Fm·...·Fn-1 - Fn = 2.
But 2 has only two factors: 1 and 2. Being odd, Fermat numbers are not divisible by 2. Hence t = 1, which proves the lemma.
Reference
- M. Aigner, G. Ziegler, Proofs from THE BOOK, Springer, 2000
- G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers, Fifth Edition, Oxford Science Publications, 1996.
- Infinitude of Primes
- Infinitude of Primes - A Topological Proof
- Infinitude of Primes - A Topological Proof without Topology
- Infinitude of Primes Via *-Sets
- Infinitude of Primes Via Coprime Pairs
- Infinitude of Primes Via Fermat Numbers
- Infinitude of Primes Via Harmonic Series
- Infinitude of Primes Via Lower Bounds
- New Proof of Euclid's Theorem
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