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Given any 10 4-element subsets of an 11-set, some two of the subsets intersect in at least two elements.

Count the ordered pairs (A,B), where A is a given 4-element subset and B is one of A's 2-element subsets, in two ways. There are 10 choices for A and, for each choice, there are 6 2-element subsets B of A. Hence there are 10*6=60 such ordered pairs. There are 55 2-element subsets of the 11-set. Let ai, for i=1,...,55 be the number of given 4-element subsets which contain the i-th 2-element subset. Then the number, 60, of ordered pairs (A,B) is the sum of the 55 ai's. Hence the average value of the ai is 60/55>1, and so some ai2. This means some 2-element subset is contained in two of the given 4-element subsets.


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