2||0|88|0| 0|0|0|||||Pondering the Delian Problem|Ian|1|11:01:51|09/10/2010|Hi%2C I was just reading the article on showing that the Delian problem is solvable and wondered about a few things. I was hoping that someone could explain the thought process%2C etc%2C to me. %0D%0A%0D%0ATo my knowledge%2C the Delian problem does not exhibit a solution because the only instruments permitted to be used are a straight edge %28a ruler with no measurements%29 and a compass. What is bothering me is%2C how is it proposed to mark root of 2 and other numbers on the triangles as suggested if root of 2 cannot be calculated with a straight edge and compass%3F And also%2C I must be missing something%2C but when I consider the dimensions of all the shapes involved%2C I do not land up with a cube... Have I missed something%3F%0D%0A%0D%0ARegards%2C%0D%0AIan 2|1|0|||||RE%3A Pondering the Delian Problem|alexb||11:18:00|09/10/2010|If you refer to this page%0D%0A%0D%0Ahttp%3A%2F%2Fwww.cut-the-knot.org%2FCurriculum%2FGeometry%2FDelian.shtml%0D%0A%0D%0Athen I wonder whether you missed the title %0D%0A%0D%0A%5Bh3%5DWhat Is Wrong%3F%5Bbr%5D%0D%0A%28Delian Problem Solved%29%5B%2Fh3%5D%0D%0A%0D%0AI believe that the title gives all the necessary indication that wht follows contains some kind of error. It does not say explicitly where.%0D%0A%0D%0Asqrt%282%29 is constructible as is any other square root of an integer. This is just the diagonal of a unit square. The cube root of 2%2C on the other hand%2C is not constructible and the Delian problem clearly contradicts this thesis.%0D%0A%0D%0ABeing able to construct the cube root of 2 would solve the Delian problem because the cube with that side would have the volume of 2 which is twice the volume of the unit cube.