Cut the knot: learn to enjoy mathematics
A math books store at a unique math study site. Shopping at the store helps maintain the site. Thank you.
Ask a tutor for free
Learning Math Online

Sites for parents
Terms of use
Awards
Interactive Activities

CTK Exchange
CTK Wiki Math
CTK Insights - a blog
Math Help

III Millennium Olympiad

Games & Puzzles
What Is What
Arithmetic/Algebra
Geometry
Probability
Outline Mathematics
Make an Identity
Book Reviews
Stories for Young
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
Visual Illusions
My Logo
Math Poll
Cut The Knot!
MSET99 Talk
Other Math sites
Front Page
Movie shortcuts
Personal info
Privacy Policy

Guest book
News sites

Recommend this site

Sites for parents

Education & Parenting

Manifesto  |  Bookstore  |  Contents  |  Amazon store  |  Term index  |  What changed?  |  Contact  |  Recommend
RSS Feed: Recent changes at CTK

Sketch of a Proof by Birkhoff and MacLane

Consider the polynomial P(z) as a mapping from one copy of the complex plane (say, the z-plane) to another copy of the complex plane (say, the w-plane). Such a mapping transforms a circle |z| = r of radius r into a closed curve on the w-plane (see Figure 1). For very large values of r, the anz n term dominates, and the image is a closed curve which loops n times around the origin of the w-plane (see Figure 2). On the other hand, for very small values of r, we may neglect all the terms except amz m + a0, where am is the coefficient with the lowest index m>0 which is not equal to zero, and the image loops m times around the point w = a0 (Figure 3). As r0, the image collapses to the point a0. We now invoke the topological fact that if we start with r very large, and continuously reduce r to 0, simultaneously reducing the image in the w -plane from a large loop encircling the origin (likely more than once) to a point, we must necessarily encounter a stage where the image curve passes through the origin w = 0. Thus, we have shown that some point on the z-plane maps to w = 0 – that is, that there is a complex root of P(z). (For details, see Birkhoff & MacLaine, A Survey of Modern Algebra, AK Peters, 1997)

Figure 1. Image of circle |z| = 2 under the mapping P(z) = z3 - 2z2 + z - 1. Figure 2. Image of circle |z| = 20 under the mapping P(z) = z3 - 2z2 + z - 1.
Figure 3. |z| = 0.1 under the mapping P(z) = z3 - 2z2 + z - 1. Note the enlarged scale. Figure 4. Image of circle |z| = 0.75 under the mapping P(z) = z3 - 2z2 + z - 1. Apparently a root of this polynomial lies very near this circle.

Copyright © 1996-2009 Alexander Bogomolny

34382886Page copy protected against web site content infringement by Copyscape

Search:
Keywords:

Google
Web CTK