Subject: Re: Multi-stage Monty Hall problem
Date: Sun, 14 Dec 1997 23:00:05 -0500
From: Alex Bogomolny
SWITCH-STICK:
To win, the fellow must first miss (.75) and then guess
right (.5) when switching. .75*.5 = .375
SWITCH-SWITCH
There are two independent possibilities:
The fellow picks right (.25)
The fellow misses on first pick (.75)
Looking into each case separately:
After he picked right, Monty Hall opens an empty
door, the fellow abandons the prize and switches
to an empty door. Monty Hall opens the last empty
door. Therefore to switch means to open the original
door that was the right guess to start with. The whole
sequence thus has the probability of .25.
After he picked wrong (.75), he may pick wrong again
(.5) so that the second switch necessarily leads to a win.
This sequence has the probability of .75*.5 = .375.
Summing up .375 + .25 gives .625.
You may want to try similar analysis with five
doors. Then you'll be able to generalize the
best strategy: STICK until the very last and
then SWITCH. Also note that the more doors
there are the better this strategy works.