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Date: Wed, 26 Mar 1997 23:47:32 -0500
From: James H.
Alex, thank you for pointing out where I "screwed up." Resolved the tableau;
The whole problem reads:
Use the simplex method to solve the following:
Maximize: Z = 2x1 - 6x2 [the 1 & 2 after the x are lowered]
subject to:
x1 - x2 <_ 4,
-x1 + x2 <_ 4,
x1 + x2 <_ 6,
x1,x2 >_ 0
the first tableau:
Max. Z = 2x1 - 6x2 + 0s1 + 0s2 + 0s2
x1 x2 s1 s2 s3
Cb\Cj 2 -6 0 0 0
s1 0 1 -1 1 0 0 4 pivot row
s2 0 -1 1 0 1 0 4
s3 0 1 1 0 0 1 6
Zj 0 0 0 0 0 0
Cj-Zj 2 -6 0 0 0
pivot
columm
Then, ? I am lost! Can you help?
James
Copyright © 1996-2009 Alexander Bogomolny
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