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Date: Wed, 18 Sep 1996 16:49:03
From: David Eppstein
Here's a problem to go with your page
which states the problem
There are 3n points in the plane no three of which lie on the
same straight line. Is it possible to form n triangles with
vertices at these points so that the triangles have no points in
common?
You then go on to generalize the problem to quadrilaterals, not necessarily convex. What about convex quadrilaterals? How many non-colinear points do you need in order to guarantee that you can find n disjoint convex quadrilaterals?
The answer is at least 4n+1 and at most 5n...
Copyright © 1996-2009 Alexander Bogomolny
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