191. Thébault's Problem II

Thébault's Problem II: erect two equilateral triangles on the adjacent sides of a square. Their apices together with the opposite vertex of the square form an equilateral triangle
URL: http://www.cut-the-knot.org/Curriculum/Geometry/Thebault2.shtml - 25kb - 19 Jun 2006

192. See-Saw Lemma

See-Saw Lemma: a statment of concurrency in a configuration that exhibits several additional properties
URL: http://www.cut-the-knot.org/Curriculum/Geometry/SeeSaw.shtml - 25kb - 19 Jun 2006

193. A Property of Circumscribed Quadrilaterals

A Property of Circumscribed Quadrilaterals: if a circle is inscribed in a quadrilateral, then the lines joining the points of tangency on the opposite sides pass through the point of intersection of the diagonals
URL: http://www.cut-the-knot.org/Curriculum/Geometry/CircumQuadri.shtml - 25kb - 19 Jun 2006

194. Circles And Parallels

Circles And Parallels
URL: http://www.cut-the-knot.org/Curriculum/Geometry/CirclesAndParallels.shtml - 25kb - 19 Jun 2006

195. Equilateral Triangles on Sides of a Quadrilateral

Equilateral Triangles on Sides of a Quadrilateral: if equilateral triangles are erected on the sides of an quadrilateral in a certain way, a parallelogram emerges
URL: http://www.cut-the-knot.org/Curriculum/Geometry/ParaFromTri.shtml - 25kb - 19 Jun 2006

196. Pedal Triangle and Isogonal Conjugacy

Pedal Triangle and Isogonal Conjugacy: pedal triangle is orthologic to the base triangle and a consequence of this fact
URL: http://www.cut-the-knot.org/Curriculum/Geometry/OrthologicPedal.shtml - 25kb - 19 Jun 2006

197. Pascal's theorem

Demonstration of Pascal's theorem for the mystic hexagon
URL: http://www.cut-the-knot.org/Curriculum/Geometry/Pascal.shtml - 25kb - 19 Jun 2006

198. The Radical Axis of Circles Inscribed in a Circular Segment

The Radical Axis of Circles Inscribed in a Circular Segment passes through the midpoint of the arc opposite the segment
URL: http://www.cut-the-knot.org/Curriculum/Geometry/IncircleInSegment1.shtml - 25kb - 19 Jun 2006

199. Equal Incircles Theorem

Equal Incircles Theorem: cevians from the apex of a triangle split into smaller triangles of level 1. Combined by 2 they form triangles of level 2, etc. If incircles of all level 1 triangles are equal, the same holds for all higher levels
URL: http://www.cut-the-knot.org/Curriculum/Geometry/AdjacentIncircles.shtml - 25kb - 19 Jun 2006

200. Clifford's Lemma

Clifford's Lemma: four intersecting circles produce four pairs of points. If four points taken one form each pair are concyclic, then so are the remaining four
URL: http://www.cut-the-knot.org/Curriculum/Geometry/CliffordTheorem.shtml - 25kb - 19 Jun 2006

Results Pages: [ << Previous ] 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 [ Next >> ]

Search Tips - Main Page