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Forum URL: http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name: Guest book
Topic ID: 521
#0, Bertrands Paradox
Posted by Yogesh Janghel on Mar-29-06 at 07:04 AM
Hi
Dont know whether the solution is correct or not.But i think if we draw a circle and then inscribe a triangle say ABC.
Then draw a tangent to the circle at point B say DBE.

Now if the chord starting from point B has to be greater than the side of the Triangle ABC it has to lie in between angle ABC=60 degrees.

So, the probablity (of chord > side of triangle ABC)< 60/180=1/3

Comments are welcome.

regards