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Forum URL: http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name: College math
Topic ID: 708
Message ID: 2
#2, RE: Union of components in Riemann sphere is closed
Posted by George on Jan-31-09 at 11:45 AM
In response to message #1
I think I have found a proof:

If {x_n} is a sequence in the union of the components which converges to some point x, then x is in P since P is closed. For each n choose a point y_n in Q which lies in the same component as x_n. Since Q is compact there is a subsequence {y_n_i} which converges to some point y in the intersection of P and Q. Suppose x and y lie in different components of P, then there exists a number c>0 such that every sequence of points joining the points a and b in the set P has a characteristic number greater than or equal to c (this is proven on page 30 of the book by Saks and Zygmund mentioned above: "By the characteristic number of a finite sequence a_1,a_2,...,a_n of points of the plane we shall mean the largest of the distances
d(a_k, a_(k+1)) between consecutive points of this sequence. If all points of a finite sequence a=a_1,a_2,...,a_n=b belong to a certain set A, we say that this sequence joins the points a and b in A") But one can derive a contradiction since a closed set in the plane is connected if and only if for every c>0 it is possible for every two points a and b of this set to be joined in it by a finite sequence of points with characteristic number < c (Cantor's condition) (page 25 of the book) and for each i, x_n_i and y_n_i lie in the same component so, for every c>0, a finite sequence of points in P with characteristic < c and joining x and y can be found