#12, RE: difficult sequence, areas partitioned in circle ,
Posted by Pierre Charland on Jan-20-06 at 08:59 PM
In response to message #11
CORRECTION: 18 should be 22 in my previous answer,
(I can't do anything without my calculator!)If k=n(n-1)/2 then ((n(n-1)/2)^2+(n(n-1)/2)+2)/2 = (n^4-2n^3+3n^2-2n+8)/8 giving 1, 2, 7, 22, 56, 121, 232, 407, 667, 1036, 1541, 2212, ...
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