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Forum URL: http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name: College math
Topic ID: 462
Message ID: 3
#3, RE: tetrahedron calculation
Posted by Jeff Jencks on Jun-28-04 at 04:20 PM
In response to message #2
Let me make sure I've got this.

I don't understand "extended intersect" or "in K". I think what you are saying is that K is a point halfway between B and C and therefore along the same line as AQ if AQ was extended. Correct?

How do you know that QK=AQ/3. Is that a known law or is there a formula that tells you that. I have the same question for SO=SQ*3/4.

I've learned the theorem of cosines but I don't remember it off the top of my head. I've been known to get sine, cosine, cosecant and cotangent mixed up.