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Forum URL: http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name: This and that
Topic ID: 62
Message ID: 1
#1, RE: x^2 y^n = z^(2n)
Posted by alexb on Dec-30-00 at 08:13 PM
In response to message #0
Dear Boaz:

> I wonder if you happened to know
> whether the expression
> x^2 + y^n = z^(2n) was ever addressed.
> x,y,z integers, n is odd >=3

No, I can't say anything about it. I would post a question like this to the sci.math newsgroup. There's a recent thread on Beal's conjecture, so there must be people out there who may help you with your question. Here's a short page on Beal's conjecture:

http://www.maa.org/devlin/devlin_12_97.html

> in one of your
> you wrote "enough to the wise"
> the original saying, which looks
> to fit better, is: "enough to the
> wise with a hint"

For me, the beauty of the Hebrew saying is in its compactness. Of course, there's an implied background, a view point annunciated just beforehand. Which presumably should suffice for the wise all by itself. "Vedai lehaham" is just an extended period which a haham should not need. To say that the above background is a hint to a deeper meaning is to deny that it's addressed to a haham.

But of course I may be mistaken.

Thank you for the kind words.

All the best,
Alexander Bogomolny