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Forum URL: http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name: This and that
Topic ID: 619
Message ID: 2
#2, RE: a + b divides a^3 + b^3
Posted by Koko on Jun-16-05 at 06:48 AM
In response to message #1
Thanks.
I am interested in the problem of finding a, b, c, and d which satisfy

a^3 + b^3 + c^3 = d^3

I have so far found the following, which of course does not generate all possible a, b, c, and d:

a = 9x^3 - 1
b = 9x^4 - 3x
c = 1
d = 9x^4

Also, I think it is possible to choose integers p and q:

d = p + q
c = p
a^3 + b^3 = q^3 + 3pq( p + q )

and now also:

( a + b )( a^2 + b^2 - ab) = ( d - c )( d^2 + c^2 + cd )

Is this any progress towards solving the problem?