#2, RE: Help no one else seems to be able to give me...
Posted by JJ on Jan-24-07 at 05:01 AM
In response to message #1
z = x^(y-x) = exp((y-x)ln(x)) dz/dx = z*(((y - x)/x) - ln(x)) = 0 (y - x)/x) - ln(x) = 0 y = x x*ln(x) = x*(1 ln(x)) = x*ln(e*x) Let Y = e*y and X = e*x then : Y = X*ln(X) The roots of this kind of equation cannot be expressed in terms of elementary function, but in term of the special function named the "Lambert's W function". See : http://mathworld.wolfram.com/LambertW-Function.html The result is : X = exp(W(Y)) Finally : x = exp(W(e*y)-1) . Remark : In case of some particular value of y, eventually this special function may be reduced to an elementary function.
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