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Forum Name:
High school
Topic ID:
163
Message ID:
4
#4, RE: solving exponential equations
Posted by Zacksg1 on Jan-25-04 at 07:18 PM
In response to message #0
x^2=2^x
2log(x)=xlog(2) take the log of both sides
log(x)/x= log(2)/2
x=2