Represent 6 with 3 identical digits using only the usual arithmetic operations, factorials and square roots

Solution

(1 + 1 + 1)!	= 6
2 + 2 + 2	= 6
3×3 - 3	= 6
√4 + √4 + √4	= 6
5/5 + 5	= 6
6×6/6	= 6
7 - 7/7	= 6
8 - √(√(8 + 8))	= 6
√(9×9) - √9	= 6
(0! + 0! + 0!)!	= 6

Both the problem and its solution have been submitted by Tobias Danielsson.

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