Outline Mathematics
Geometry

Construction of the Angle Bisector

The angle bisector of an angle is one of the most common and elementary point loci in geometry. The angle bisector of an angle is the locus of points equidistant from the sides of the angle. Of course the notion of angle needs to be defined accurately. (In the applet, the angle is defined by two vectors AB and AC with moveable endpoints.)

Euclid gives the construction in (I.9).

 

This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


Let angle be BAC. Euclid picks point D on AB and construct E on AC so that AE = AD. He then forms an equilateral,scalene,isosceles,equilateral triangle (I.1) DEF and shows that AF is the angle bisector of BAC. As far as logical purity is concerned this is all that is needed to construct a line: the construction is frugally based on the previously established construction and gives exactly what it was set to produce.

The construction presented by the applet is virtually the same, except the common radius of the circles drawn at D and E is no longer required to be DE. The proof is actually the same as before, but the result is more general and better relates to the locus property of the line. I'd say this is a different kind of frugality: getting more for the same effort.

So let AE = AD,AD,DE,BC,BD and circles are drawn centered at D and E and equal radii. The common radius should be chosen so as to make the circles intersect,coincide,exist,intersect. A sure way to achieve this is to choose a radius greater than,greater than,equal to,smaller than AD. Let F be one of the two points of intersection of the circles. (The applet selects the point farthest from A.)

Consider two triangles ADF and AEF,BCD,AEF,ABD,BCD. They share a side AF, have AD = AE,AD,DF,EF,BC,AE and also DF = EF,AD,DF,EF,BC,AE by the construction. They are therefore equal by SSS,SAS,ASA,SSS, (I.8). The angles DAF and EAF correspond to each other and, hence, are equal. These are the two halves of angle BAC.

References

  1. T. L. Heath, Euclid: The Thirteen Books of The Elements, v. 1, Dover, 1956

Related material
Read more...

  • Construction of the Perpendicular Bisector
  • Existence of the Circumcenter
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