Simultaneous Generalization of the Theorems of Ceva and MenelausCeva's and Menelaus' theorems are useful tools in establishing concurrency of lines and collinearity of points. Ceva's theorem is an easy consequence of Menelaus' and the opposite is also true. Although similar, the two theorems work in complementary circumstances. Let A1A2A3 be a triangle with points B1, B2, B3 in sidelines A2A3, A1A3, and A1A2, respectively. Ceva's theorem holds when an even number (0 or 2) of points B are internal to the sides of ΔA1A2A3; Menelaus's theorem holds otherwise, when an odd number (1 or 3) of points B are internal to the sides of the triangle. According to Ceva's theorem, the cevians AiBi are concurrent provided
According to Menelaus' theorem, the three points Bi are collinear provided
The converse theorems are also true and are easily shown by contradiction to be equivalent to the direct statements. Note that all the segments involved are thought to be directed so that, for example, Assume b1, b2, b3 are real numbers such that
so that b1b2b3 = 1 for Ceva's and b1b2b3 = -1 for Menelaus' theorems. We now place additional three points C1, C2, C3 on the side lines A2A3, A1A3, and A1A2. The real numbers c1, c2, c3 play the role similar to that of b1, b2, b3, with a change of direction, for example, TheoremC1B2, C2B3 and C3B1 are concurrent iff
ProofFor the proof we'll use the barycentric coordinates. For any point, P in the plane of ΔA1A2A3 the barycentric coordinates p1:p2:p3 could be found starting with the signed areas of triangles A1A2P, A2A3P and A3A1P:
where, say, the area [A1A2P] is positive if triangles A1A2P and A1A2A3 have the same orientation and is negative otherwise. In other words, [A1A2P] is positive iff P is on the same side of A1A2 as A3. The barycentric coordinates are hommogeneous, meaning that, for any real k≠0,
In barycentric coordinates, B1(0:b1:1), B2(1:0:b2), B3(b3:1:0) and, correspondingly, C1(0:c1:1), C2(1:0:c2), C3(c3:1:0). Let X(x1:x2:x3) be a generic variable point in the plane of ΔA1A2A3. Then the lines B1C3, B2C1, and B3C2 are given by the determinant equations
These reduce, respectively, to
These three lines are concurrent iff their equations are linearly dependent which is only true when
which is exactly b1b2b3 + c1c2c3 + b1c1 + b2c2 + b3c3 = 1. Observe that if C1, C2, C3 coincide with A2, A3, A1, respectively, then I placed an interactive illustration on a Theorems of Ceva and Menelaus, an Illustrated Generalizationseparate page. References
Barycenter and Barycentric Coordinates
Menelaus and Ceva
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