Cut the knot: learn to enjoy mathematics
A math books store at a unique math study site. Shopping at the store helps maintain the site. Thank you.
Ask a tutor for free
Learning Math Online

Sites for parents
Terms of use
Awards
Interactive Activities

CTK Exchange
CTK Wiki Math
CTK Insights - a blog
Math Help

III Millennium Olympiad

Games & Puzzles
What Is What
Arithmetic/Algebra
Geometry
Probability
Outline Mathematics
Make an Identity
Book Reviews
Stories for Young
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
Visual Illusions
My Logo
Math Poll
Cut The Knot!
MSET99 Talk
Other Math sites
Front Page
Movie shortcuts
Personal info
Privacy Policy

Guest book
News sites

Recommend this site

Sites for parents

Education & Parenting

Manifesto  |  Bookstore  |  Contents  |  Amazon store  |  Term index  |  What changed?  |  Contact  |  Recommend
RSS Feed: Recent changes at CTK

Equidecomposition of a Triangle and a Rectangle: What is this about?
A Mathematical Droodle


This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


Buy this applet
What if applet does not run?

Explanation

Copyright © 1996-2009 Alexander Bogomolny

 

 

 

 

 

 

 

 

 

 

 

 

 

 

The applet purports to illustrate a simple fact:

  A triangle can be cut into three pieces which, after translation and rotation, combine into a rectangle of equal area.

It is said that the triangle and rectangle are equidecomposable. In general two shapes are equidecomposable, provided one could be cut into pieces, which can be rearranged into the second shape. The decomposition of a triangle into a rectangle is pretty tame, but there are rather weird ones. Much depends on what kind of a cut is allowed. The one we are concerned with here may be called decomposition by dissection. It is characterized by the fact that, as sets, any two adjacent pieces both contain their common boundary. The decomposition in the Tarski-Banach paradox is different. The pieces there, adjacent or not, have an empty intersection.

Note that the above demonstration does not prove that any triangle and rectangle of equal areas are equidecomposable, although they in fact are.

This demonstration does teach us serendipitously that the area of a triangle is the product of the base times half its altitude to the base:

  AreaOfTriangle = base × altitude/2.

(The approach that is more readily interpreted as

  AreaOfTriangle = (base × altitude) / 2

is considered elsewhere.)

Finally note that any rectangle is equidecomposable with a square. Thus we can also claim that any triangle is equidecomposable with a square.

Equidecomposition by Dissection

  1. Carpet With a Hole
  2. Equidecomposition of a Rectangle and a Square
  3. Equidecomposition of Two Parallelograms
  4. Equidecomposition of Two Rectangles
  5. Equidecomposition of a Triangle and a Rectangle
  6. Equidecomposition of a Triangle and a Rectangle II
  7. Perigal's Proof of the Pythagorean Theorem
  8. Two Symmetric Triangles Are Directly Equidecomposable
  9. Wallace-Bolyai-Gerwien Theorem

Copyright © 1996-2009 Alexander Bogomolny

34383163Page copy protected against web site content infringement by Copyscape

Search:
Keywords:

Google
Web CTK