Orthodiagonal and Cyclic Quadrilaterals: What Is This About?
A Mathematical Droodle
| |
|
Explanation
Copyright © 1996-2008 Alexander Bogomolny
The applet below provides an illustration to a problem from an outstanding collection by T. Andreescu and R. Gelca:
| |
Let ABCD be a convex quadrilateral such that the diagonals AC and BD are perpendicular, and let P be their intersection. Prove that the reflections of P with respect to AB, BC, CD, and DA are concyclic.
|
| |
|
The quadrilateral in question is a dilation with coefficient 2 of the quadrilateral formed by projections of P on the sides of quadrilateral ABCD. It suffices to prove that the latter is cyclic. Let X, Y, Z, W be the feet of perpendiculars from P to the sides AB, BC, CD, DA. The quadrilaterals AXPW, BYPX, CZPY, DWPZ are cyclic as having a pair of opposite right angles. From this we obtain the following identities:
| |
WAP = WXP,
PXY = PBY,
YZP = YCP,
PZW = PDW.
|
In triangles APD and BPC we have
| |
WXY + WZY | = WXP + PXY + YZP + PZW |
| | = WAP + PDW + PBY + YCP |
| | = 90o = 90o |
| | = 180o, |
|
which indeed shows that quadrilateral XYZW is cyclic.
References
- T. Andreescu, R. Gelca, Mathematical Olympiad Challenges, Birkhäuser, 2004, 5th printing, 1.2.5 (p. 9)
Copyright © 1996-2008 Alexander Bogomolny
|