Nine Point Circle: an Elementary Proof

In any triangle, the orthocenter and the circumcenter are collinear with center N of circle that passes through the midpoints of the sides, the feet of the altitudes, and the midpoints of the segments joining the orthocenter with the vertices. The radius of the circle is half the circumradius. In addition, HN = NO

The circle is known as the 9-point circle and its center as the 9-point center.

Discussion

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Copyright © 1996-2012 Alexander Bogomolny

The key to the proof is the observation that the antipodes of the vertices in the circumcircle along with the orthocenter and two vertices form parallelograms whose diagonals intersect at the midpoints of the sides of the triangle. We already used this observation twice: when proving that reflections of the orthocenter in the side lines of a triangle lie on its circumcenter, and in a simple proof of the existence of the Euler line.

Let H_a, M_a, S_a be the foot of the altitude from A, the midpoint of the side BC (opposite A) and the midpoint of AH. Points H_b, M_b, S_b, H_c, M_c, S_c are defined similarly. AD, BE, and CF are diameters of the circumcircle of ΔABC.

Let's focus on vertex C and its antipode F, so that CF is a diameter of the circumcircle. As we know, HD passes through M_c and is divided by M_c into halves: HM_c = DM_c.

By definition, also HS_c = CS_c, implying that M_cS_c is a midline of ΔCHD so that M_cS_c||CD. Let N be the intersection of M_cS_c and HO: HN = NO. Now, in ΔDHO, EM_c = OD/2. If R is the circumradius of ΔABC then OD = R and we have EM_c = R/2. In ΔCHO, EH_c = R/2.

As was already shown, HH_c = K_cH_c. It follows that in ΔHOK_c NH_c is the midline parallel to OK_c = R.

To summarize, NS_c = NM_c = NK_c = R/2. Similarly we show that the remaining six points also lie on the circle with center N and radius R/2.

N is another famous point (along with the orthocenter, centroid, and circumcenter) that lies on the Euler line. The 9-point circle is also known as Euler's circle and sometimes Feuerbach's circle.

(Note: Another simple argument can be found elsewhere at the site.)

Nine Point Circle

• Nine Point Circle: an Elementary Proof
• Feuerbach's Theorem
• Feuerbach's Theorem: a Proof
• Four 9-Point Circles in a Quadrilateral
• Four Triangles, One Circle
• Hart Circle
• Incidence in Feuerbach's Theorem
• Six Point Circle
• Nine Point Circle
• 6 to 9 Point Circle
  • Six Concyclic Points
• Six Concyclic Points II
• Bevan's Point and Theorem

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Copyright © 1996-2012 Alexander Bogomolny