Inscriptible Quadrilateral: An IllustrationThe applet below illustrates the theorem of Pitot. For a quadrilateral ABCD circumscribed around a circle the sums of opposite sides are equal: AB + CD = BC + DA.
The commonly given proof of the converse contains a subtle flaw which is not at all simple to fix. But an additional proof smoothes the wrinkles. |Activities| |Contact| |Front page| |Contents| |Geometry| |Store| Copyright © 1996-2012 Alexander Bogomolny |
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